A 7.80 x 10-3opposite direction as the bullet is displaced 4.80 x 10-2 m. As a result, the bullet comes to a stop. What is the work done by thesuperhero in stopping the bullet? {Consider the change in kinetic energy}kg bullet is initially moving horizontally at v, = + 630 m/s. Along comes a superhero and exerts a constant force F in theO-1,890 JO- 1,550 JO-1,240 JO-2,370 J2-1,396 JM36comm and

Hey dear this question is from work energy theorem .I solved it in a easy way. Have a look

A 7.80 x 10 3 kg bullet is initially moving horizontally at v, = + 630 m/s. Along comes a superhero and exerts a constant force F in the opposite direction as the bullet is displaced 4.80 x 10-2 m. As a result, the bullet comes to a stop. What is the work done by the superhero in stopping the bullet? {Consider the change in kinetic energy} 3-1,890 J O- 1,550 J 2-1,240 J O-2,370 J O-1,396 J

A 7.80 x 10 3 kg bullet is initially moving horizontally at v, = + 630 m/s. Along comes a superhero and exerts a constant force F in the opposite direction as the bullet is displaced 4.80 x 10-2 m. As a result, the bullet comes to a stop. What is the work done by the superhero in stopping the bullet? {Consider the change in kinetic energy} 3-1,890 J O- 1,550 J 2-1,240 J O-2,370 J O-1,396 J