(a) A parallel plate capacitor consists of plates with area of cross section of 250 cm², (i) What is the capacitance in pF when distance between them is 1 mm and the dielectric is air? (ii) Calculate the value of capacitance in pF if the space between the capacitors is filled with a dielectric with relative permittivity of 3.7. (2 Marks) Consider ɛ0 = 8.854 x 10-12 F/m (b) Find the Equivalent Capacitance of the following circuit, when C1=15 µF; C2=10 µF; C3=47 µF; C4=22 µF ; C5-15 μF; C6=68 μF; (2 Marks) C2 C3 H C1 HH C4 C5 C6 Ceq

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter19: Capacitors
Section: Chapter Questions
Problem 3RQ: A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted...
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 (a) 

(i) Capacitance in pF if dielectric material is air = 

Answer and unit for part 1

(ii) Capacitance in pF if dielectric with relative permittivity of 3.7 is used = 

Answer and unit for part 2

Q23 (b) 

Equivalent Capacitance (Ceq) = 

Answer and unit for part 3
(a) A parallel plate capacitor consists of plates with area of cross section of 250 cm?, (1) What is the capacitance
in pF when distance between them is 1 mm and the dielectric is air? (ii) Calculate the value of capacitance in pF
if the space between the capacitors is filled with a dielectric with relative permittivity of 3.7. (2 Marks)
Consider ɛ0 = 8.854 x 10 12 F/m
(b) Find the Equivalent Capacitance of the following circuit, when C1=15 µF; C2=10 µF; C3=47 µF; C4=22 µF
; C5=15 µF; C6=68 µF; (2 Marks)
C2
C3
H
C1
HH
C4
C5
C6
Ceq
Transcribed Image Text:(a) A parallel plate capacitor consists of plates with area of cross section of 250 cm?, (1) What is the capacitance in pF when distance between them is 1 mm and the dielectric is air? (ii) Calculate the value of capacitance in pF if the space between the capacitors is filled with a dielectric with relative permittivity of 3.7. (2 Marks) Consider ɛ0 = 8.854 x 10 12 F/m (b) Find the Equivalent Capacitance of the following circuit, when C1=15 µF; C2=10 µF; C3=47 µF; C4=22 µF ; C5=15 µF; C6=68 µF; (2 Marks) C2 C3 H C1 HH C4 C5 C6 Ceq
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