A Aluminum L = 3 ft A = 0.75 in.² E = 10 x 106 psi 2ft 3 ft. с B Bronze L = 4 ft A = 0.25 in.² E = 12 x 106 psi D
A Aluminum L = 3 ft A = 0.75 in.² E = 10 x 106 psi 2ft 3 ft. с B Bronze L = 4 ft A = 0.25 in.² E = 12 x 106 psi D
Chapter5: Beams And Frames: Shear And Bending Moment
Section: Chapter Questions
Problem 53P: For the beam shown: (a) determine the distance a for which the maximum positive and negative bending...
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Transcribed Image Text:A
Aluminum
L = 3 ft
A = 0.75 in.²
E = 10 x 106 psi
2ft 3 ft.
с
B
Bronze
L = 4 ft
A = 0.25 in.²
E = 12 x 106 psi
P
-2 ft2 ft →
FIG. P2.23
D
Transcribed Image Text:2.23 The rigid bars AB and CD are supported by pins at A and D. The vertical
rods are made of aluminum and bronze. Determine the vertical displacement of the
point where the force P = 10 kips is applied. Neglect the weights of the members.
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