(a) Among nine randomly selected goblets, how likely is it that only one is a second? Recall that the formula for calculating binomial pmf probabilities is: b(x; n, p) = where x represents the number of successes (S), n represents the number of trials, and p represents the probability of success, P(S). Also recall that (:). ni C Tn- x)lx A company that produces fine crystal knows from experience that 18% of its goblets have cosmetic flaws and must be classified as "seconds." Nine goblets are randomly selected and we are asked to find the probability that only one goblet is a "second." Thus, and x Therefore, in this situation, we have: b

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
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This question has multiple parts. Can fill in the boxes for part A

A company that produces fine crystal knows from experience that 18% of its goblets have cosmetic flaws and must be classified as "seconds."
(a) Among nine randomly selected goblets, how likely is it that only one is a second?
(b) Among nine randomly selected goblets, what is the probability that at least two are seconds?
(c) If goblets are examined one by one, what is the probability that at most five must be selected to find four that are not seconds?
Step 1
(a) Among nine randomly selected goblets, how likely is it that only one is a second?
Recall that the formula for calculating binomial pmf probabilities is:
b(x; n, p) =
p*(1 p)"-
where x represents the number of successes (S), n represents the number of trials, and p represents the probability of success, P(S). Also recall that
(:) -
n!
= Cn, x =
(n-x)!x!
A company that produces fine crystal knows from experience that 18% of its goblets have cosmetic flaws and must be classified as "seconds." Nine goblets are randomly selected and we are asked to find the probability that only one goblet is a "second." Thus,
p =
,n =
, and x =
Therefore, in this situation, we have: b
Transcribed Image Text:A company that produces fine crystal knows from experience that 18% of its goblets have cosmetic flaws and must be classified as "seconds." (a) Among nine randomly selected goblets, how likely is it that only one is a second? (b) Among nine randomly selected goblets, what is the probability that at least two are seconds? (c) If goblets are examined one by one, what is the probability that at most five must be selected to find four that are not seconds? Step 1 (a) Among nine randomly selected goblets, how likely is it that only one is a second? Recall that the formula for calculating binomial pmf probabilities is: b(x; n, p) = p*(1 p)"- where x represents the number of successes (S), n represents the number of trials, and p represents the probability of success, P(S). Also recall that (:) - n! = Cn, x = (n-x)!x! A company that produces fine crystal knows from experience that 18% of its goblets have cosmetic flaws and must be classified as "seconds." Nine goblets are randomly selected and we are asked to find the probability that only one goblet is a "second." Thus, p = ,n = , and x = Therefore, in this situation, we have: b
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