a= b= A 2 B 6 E 9 Therefore, a= of (EF). GCD (a, b). From a and b, find: B 6 с 2 LL F 5 2 D 5 D 5 (combination of BCD) and b = E 9 F 5 (combination

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.1: Equations
Problem 75E
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Question
A
B
D
E
F
2
6
2
5
9
5
В
D
a =
2
F
b=
Therefore, a=
(combination of BCD) and b=
(combination
of (EF). GCD (a, b).
From a and b, find:
Transcribed Image Text:A B D E F 2 6 2 5 9 5 В D a = 2 F b= Therefore, a= (combination of BCD) and b= (combination of (EF). GCD (a, b). From a and b, find:
a) Greatest Common Divisor (GCD)fora and b by using Euclidean algorithm.
b) s and t by usingthe formula d = sa + tb based on answer obtainedfrom (a)
Transcribed Image Text:a) Greatest Common Divisor (GCD)fora and b by using Euclidean algorithm. b) s and t by usingthe formula d = sa + tb based on answer obtainedfrom (a)
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