A ball is thrown straight down from the top of a 482-foot building with an initial velocity of -15 feet per second. Use the position function below for free-falling objects. s(t) = -16t2 + v0t + s0 What is its velocity after 4 seconds? v(4) = ft/s What is its velocity after falling 189 feet? v = ft/s I found the answer for the first part, which is -143 ft/sec. When I solved the second one, I got -137.88, and it says that is incorrect. So i need help with the second question please
A ball is thrown straight down from the top of a 482-foot building with an initial velocity of -15 feet per second. Use the position function below for free-falling objects. s(t) = -16t2 + v0t + s0 What is its velocity after 4 seconds? v(4) = ft/s What is its velocity after falling 189 feet? v = ft/s I found the answer for the first part, which is -143 ft/sec. When I solved the second one, I got -137.88, and it says that is incorrect. So i need help with the second question please
Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
1st Edition
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:HOUGHTON MIFFLIN HARCOURT
Chapter9: Solving Quadratic Functions
Section: Chapter Questions
Problem 12CT
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A ball is thrown straight down from the top of a 482-foot building with an initial velocity of -15 feet per second. Use the position function below for free-falling objects.
s(t) = -16t2 + v0t + s0
What is its velocity after 4 seconds?
v(4) = ft/s
What is its velocity after falling 189 feet?
v = ft/s
v(4) = ft/s
What is its velocity after falling 189 feet?
v = ft/s
I found the answer for the first part, which is -143 ft/sec. When I solved the second one, I got -137.88, and it says that is incorrect. So i need help with the second question please
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