A balloon is descending vertically at a constant rate of 6 ft/sec to land on a level, straight road. Justwhen the balloon is 104 feet above the ground, a bicycle moving at a constant rate of 15 ft/sec passesdirectly under it (point 0 on the diagram).How fast is the distance between the bicycle and balloon changing 4 seconds later?a.b.dog stand that the cyclist passed 8 seconds before passing directly under the balloon. If an observermunching their hot dog while standing at this location watches the balloon descend, at what angular ratedo their eyes rotate downward to watch the balloon descend at the moment the balloon is 30 feet high?Extend the horizontal line in the diagram above to the left in order to find the location of a hot

Hello. Since your question has multiple parts, we will solve first question for you. If you want…

A balloon is descending vertically at a constant rate of 6 ft/sec to land on a level, straight road. Just when the balloon is 104 feet above the ground, a bicycle moving at a constant rate of is ft/sec passes directly under it (point 0 on the diagram). How fast is the distance between the bicycle and balloon changing 4 seconds later?

A balloon is descending vertically at a constant rate of 6 ft/sec to land on a level, straight road. Just when the balloon is 104 feet above the ground, a bicycle moving at a constant rate of is ft/sec passes directly under it (point 0 on the diagram). How fast is the distance between the bicycle and balloon changing 4 seconds later?

College Algebra

1st Edition

ISBN:9781938168383

Author:Jay Abramson

Publisher:Jay Abramson

Chapter6: Exponential And Logarithmic Functions

Section6.1: Exponential Functions

Problem 60SE: The formula for the amount A in an investmentaccount with a nominal interest rate r at any timet is...

See similar textbooks