A base line was measured in four lengths giving 30.126, 29.973, 30.066, and 22.536 m. Thedifferences of level were respectively 0.45, 0.60, 0.30, and 0.45 m. The temperature duringobservation was 10°C and the tension applied is 15 kg. The tape was standardized as 30 m,at 20°C, on the flat with a tension of 5 kg. The coefficient of expansion was 0.000011 per°C, the weight of the tape is 1 kg, the cross-sectional area is 3 mm, E=210×10³ N/mm²,gravitational acceleration g=9.80665 m/s².a. Calculate the correct distance of the baseline.b. What tension should have been applied to eliminate the sag correction?

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Answered: A base line was measured in four…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A 100‐ft steel tape standardized at 68° F and supported under a tension of 20 lb, was found to be 100.012ft long. The tape had a cross‐sectional area of 0.0078 in^2 and a weight of 0.0266lb/ft. The ground is on a smooth level grade, thus the tape will be fully supported. Assume a temperature increase of 19°F. Assume thermal coefficient equal to 0.00000645/°F Determine total correction (due to incorrect length and temperature) to be applied to lay out a horizontal distance of 175 ft.
A 0.65kg, 50m tape was standardized and supported througnout its whole length and found to be 0.00205m longer at an observed temperature of 31.8°C and a pull of 10KN. This tape was used to measure a 4% grade line which was found to be 662.702m. During measurement, the temperature is 15°C and the tape is suspended under a pull of 20KN. E=200GPa, cross- sectional area of tape is 3mm? and the coefficient of linear expansion is 0.0000116m/°C.
A 50m tape has the conditions-The standard temperature is 35degrees Celsius and the site temperature is 40degrees Celsius resulting to a temperature correction factor=0.01m for the 50 m tape -The standard pull is 6 kg but the applied pull is 2.4 kg resulting to a correction due to pull= -0.03m for the 50 m tape. a) Determine the reading to be laid out to get a length of 50m b) Determine the reading to be laid out to get a length of 1500m
A line measured in the field and found to be 1,219.00 m, with a steel tape with length of 50m, and weight of 0.70kg. The cross-sectional area of the tape is 0.03cm^2, and was standardized at a temperature of 20°C under a tension of 5kg. Find the correction of the line due to tension, temperature and sag. Find the corrected length of the line, if the distance measured in the field under tension force of 10kg and at a temperature of 35°C. The modulus of elasticity, E, is 2.10 x 10^7 kg/cm^2. K = 0.0000116 m/m°C.
a=5m and height EB=3m
A steel tape is standardized at 68°F under a tension of 15 lb when supported throughout its entire length, and the distance between the zero mark and the 100-ft mark is 99.98 ft. The tape weighs 0.013 lb/ft and a cross-sectional area of 0.0040 ??2. In the field this tape is used under a 15-lb tension and is supported at the ends only, and the temperature of the tape is recorded as 88°F throughout the measurement. A series of distances are recorded as 100.00, 100.00, 100.00 and 57.22 ft. What is the total actual or true distance after corrections for systematic errors have been applied?
A steel tape is standardized at 68°F under a tension of 15 lb when supported at the two ends only, and the distance between the zero mark and the 100-ft mark is 99.972 ft. The total weight of the tape is 2.80 lb and its cross-sectional area is 0.0088 in2. For steel E is 30,000,000 psi. What is the distance between the starting and ending points, when the tape is supported at the two ends only, the tension is 25-lb? Ex-6. A steel tape with a cross-sectional area of 0.039 cm²and weighing 0.909 kg has a length of 30.009 m. when supported throughout 20°C and subject to a tension of 5.5 kg. This tape is used to measure a distance along a uniform 4% grade and is supported throughout during the measurement. The tension applied is 12 kg. The temperature of the tape is 2°C. The measured slope distance is recorded 381.615 m. What is the corrected horizontal distance?
A 50m tape weighing 0.03kg/m is used to measure distance AB. The tape is supported at both end points and at its midspan and then applied tension is 6kg. Determine the total sag correction if the measured distance is 1,320.50m.
Q2) A line AB of slope 3% was measured with steel tape of 30m to be 175.66 m. The weighing of tape was 0.032 m / kg with cross - sectional area of 0.049 cm2 and has length of 30.02m at standard conditions of 20 ° C and a tension of 6 kg. For each time used, it was supported at three points (ends and middle) with tension of 9kg and temperature of 30 ° C. Compute the corrected horizontal distance when the modulus of? elasticity is 2.15 * 106 kg / cm2 and (a = 1.15 * 10-5 / ° C)
A 50-m steel tape weighs 0.04 kg/m and has a cross-sectional area of 0.022 sq. cm. It measures correctly when supported throughout under a tension of 8.0 kg and at a temperature of 20 degrees Celsius. When used in the field, the tape is only supported at its ends, under a pull of 9.0 kg, and at an average temperature of 28 degrees Celsius. What is the distance between the zero and 50-m mark? a.47.98 m b.50.09 m c.49.90 m d.48.89 mShow Solution please
A 30 m tape steel tape weighing 0.7 kg has a cross-sectional area of 0.03cm², and a standard length of 30.005m when fully supported, at 20°C, and with 5 kg tension.a. A line on a smooth level ground is measured with the tape under the tension of 10 kg at a temperature of 20°C and is recorded as 1242.823 m long. Compute the correction for the increase in tension. K = 2 100 000 kg /cm²b. This same tape is used to measure a distance recorded as 985.423 m over level terrain with the tape supported at the two ends and 5kg of tension (temperature of 20°C). Calculate the correction due to sag for this distance.
Nbd should be 33.3 k (C)

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