A beam of helium-3 atoms (m = 3.016 u) is incident on a target of nitrogen-14 atoms (m = 14.003 u) at rest. During the collision, a proton from the helium-3 nucleus passes to the nitrogen nucleus, so that following the collision there are two atoms: an atom of "heavy hydrogen" (deuterium, m = 2.014 u) and an atom of oxygen-15 (m= 15.003 u). The incident helium atoms are moving at a velocity of 6.346 x 106 m/s. After the collision, the deuterium atoms are observed to be moving forward (in the same direction as the initial helium atoms) with a velocity of 1.531 x 107 m/s. What is the final velocity of the oxygen-15 atoms?

A beam of helium-3 atoms (m = 3.016 u) is incident on a target of nitrogen-14 atoms (m = 14.003 u) at rest. During the collision, a proton from the helium-3 nucleus passes to the nitrogen nucleus, so that following the collision there are two atoms: an atom of "heavy hydrogen" (deuterium, m = 2.014 u) and an atom of oxygen-15 (m= 15.003 u). The incident helium atoms are moving at a velocity of 6.346 x 106 m/s. After the collision, the deuterium atoms are observed to be moving forward (in the same direction as the initial helium atoms) with a velocity of 1.531 x 107 m/s. What is the final velocity of the oxygen-15 atoms?