A boat leaves a dock at 4:00 PM and travels due south at a speed of 20 km/h. Another boat has been heading due east at 15 km/h and reaches the same dock at 5:00 PM. How many minutes after 4:00 PM were the two boats closest together?

A boat leaves a dock at 4:00 PM and travels due south at a speed of 20 km/h. Another boat has been heading due east at 15 km/h and reaches the same dock at 5:00 PM. How many minutes after 4:00 PM were the two boats closest together?

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

Chapter2: Graphical And Tabular Analysis

Section2.3: Solving Linear Equations

Problem 2TU: If you travel 300 miles on the first day and then drive v miles per hour for t hours on the second...

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Question

Solve for step 1 and whole question

A boat leaves a dock at 4:00 PM and travels due south at a speed of 20 km/h. Another boat has been heading
due east at 15 km/h and reaches the same dock at 5:00 PM. How many minutes after 4:00 PM were the two
boats closest together?
Step 1
Let t be the time, in hours, after 4:00 PM If the position of the boat at t
the position of the boat heading south at time t is
0 corresponds to the origin, then
(x, y) =
225,400
15 km/h
W
20 km/h
O Type here to search
hp
选

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