A body mass 4 kg falls (from at rest) from a medium whose resisting force is numerically equal to 0.003v, where v is the velocity in m/s. The equation for v is v = 13066.67 – which is 13066.67, is called the terminal velocity. Now, how long does it take for the body mass to reach 80% of it: 13066.67e-7.5×10¬4t . The first term on the equation, terminal velocity? O 5986.13 seconds O 2145.92 seconds O 3164.13 seconds O 1063.47 seconds O 4873.14 seconds
A body mass 4 kg falls (from at rest) from a medium whose resisting force is numerically equal to 0.003v, where v is the velocity in m/s. The equation for v is v = 13066.67 – which is 13066.67, is called the terminal velocity. Now, how long does it take for the body mass to reach 80% of it: 13066.67e-7.5×10¬4t . The first term on the equation, terminal velocity? O 5986.13 seconds O 2145.92 seconds O 3164.13 seconds O 1063.47 seconds O 4873.14 seconds
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 18EQ
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