A box with a square base and open top must have a volume of 32 cm. We wish to find the dimensions of the box that minimize the amount of material used.

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
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ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
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Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
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A box with a square base and open top must have a volume of 32 cm^3. We wish to find the dimensions of the box that minimize the amount of material used.

First, find a formula for the surface area of the box in terms of only x, the length of one side of the square base.

Simplify your formula as much as possible.
A(x)=(ans)

Next, find the derivative, A'(x).
A'(x)=(ans)

Now, calculate when the derivative equals zero, that is, when A'(x)=0.
A'(x)=0 when x= (ans)

We next have to make sure that this value of xx gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x).
A"(x)=(ans)

Evaluate A"(x) at the x-value you gave above.

(ans)

can steps be shown neatly please

A box with a square base and open top must have a volume of 32 cm. We wish to find the dimensions of
the box that minimize the amount of material used.
First, find a formula for the surface area of the box in terms of only r, the length of one side of the square
base.
Simplify your formula as much as possible.
A(x) =
Next, find the derivative, A'(x).
A' (x)
Now, calculate when the derivative equals zero, that is, when A'(x) = 0.
A' (x) = 0 when a
We next have to make sure that this value of z gives a minimum value for the surface area. Let's use the
second derivative test. Find A"(x).
A"(2) =
Evaluate A"(x) at the r-value you gave above.
Transcribed Image Text:A box with a square base and open top must have a volume of 32 cm. We wish to find the dimensions of the box that minimize the amount of material used. First, find a formula for the surface area of the box in terms of only r, the length of one side of the square base. Simplify your formula as much as possible. A(x) = Next, find the derivative, A'(x). A' (x) Now, calculate when the derivative equals zero, that is, when A'(x) = 0. A' (x) = 0 when a We next have to make sure that this value of z gives a minimum value for the surface area. Let's use the second derivative test. Find A"(x). A"(2) = Evaluate A"(x) at the r-value you gave above.
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