A bullet of mass m¡ traveling horizontally with speed u hits ablock of mass m2 (m2>>m¡) that is originally at rest and becomes embedded in the block.After the collision, the block slides horizontally a distance d on a surface with friction,and then falls off the surface at a height h as shown. The coefficient of kinetic frictionbetween the block and the surface is µk.coefficient of kinetic frictionm,m,a) What is umin, the minimum speed of the bullet so that the block falls off the surface?Express your answer in terms of some or all of the following: mı, m2, µk, d, h and g for thegravitational constant.b) Assume that the initial speed of the bullet u is large enough for the block to fall off thesurface. Calculate x, the position where the block hits the ground measured from thebottom edge of the surface. Express your answer in terms of some or all of the following:M1, m2, µk, u, d, h and g.

Since the collision of the bullet and block is inelastic so momentum is conserved, Thus, m1u=m1+m2v…

A bullet of mass m¡ traveling horizontally with speed u hits a block of mass m2 (m2>>m¡) that is originally at rest and becomes embedded in the block. After the collision, the block slides horizontally a distance d on a surface with friction, and then falls off the surface at a height h as shown. The coefficient of kinetic friction between the block and the surface is µ̟.

A bullet of mass m¡ traveling horizontally with speed u hits a block of mass m2 (m2>>m¡) that is originally at rest and becomes embedded in the block. After the collision, the block slides horizontally a distance d on a surface with friction, and then falls off the surface at a height h as shown. The coefficient of kinetic friction between the block and the surface is µ̟.