(a) By sketching the graph of the function f(x) = x³ + x² – 1, show that the equation f (x) = 0 has only one real root. (b) Show that the real root of f(x) = 0 lies in the interval [0, 1].

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 14T
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Consider the equation x^3 + x^2 - 1 = 0

(a) By sketching the graph of the function f(x) = x³ + x² – 1, show that
the equation f(x) = 0 has only one real root.
(b) Show that the real root of f(x) = 0 lies in the interval [0, 1].
(c) Analyze which one of the following three equations you will choose to
approximate the real solution of f(x) = 0 by the fixed-point iteration
method:
(i) x = (1 – x²)³
(1 – x³)
(ii) x =
(iii) x =
(d) Approximate the real solution of f(x) = 0 with an accuracy of 10-4.
Transcribed Image Text:(a) By sketching the graph of the function f(x) = x³ + x² – 1, show that the equation f(x) = 0 has only one real root. (b) Show that the real root of f(x) = 0 lies in the interval [0, 1]. (c) Analyze which one of the following three equations you will choose to approximate the real solution of f(x) = 0 by the fixed-point iteration method: (i) x = (1 – x²)³ (1 – x³) (ii) x = (iii) x = (d) Approximate the real solution of f(x) = 0 with an accuracy of 10-4.
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