(a) By sketching the graph of the function f(x) = x³ + x² – 1, show that the equation f (x) = 0 has only one real root. (b) Show that the real root of f(x) = 0 lies in the interval [0, 1].
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Consider the equation x^3 + x^2 - 1 = 0
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- Use the intermediate value theorem to show that the equation x^3+x^2−2x+1=0 has a solution i the interval [-1,0]Find the general solution of F′(x) = 1/x2, x > 0 and find the particular solution that satisfies the initial condition F(1) = 0.1. Do you agree with the contention that the functions f(x) = x + 2 and g(x) = x2 - 4 / x - 2 are the same in every respect. Provide evidence to support your position. 2. Do you agree with the statement that “ cubic functions must have at least 1x-intercept but not more than 3, whereas quadratic functions may or may not have x-intercepts.Provide evidence to support your position.
- There is a cubic function with f(3) = f (−3/2) = 0 with a turning point at the factor (x-3), and the point (2,-21) exists on the graph. Solve for the possible values of x such that −6 < f(x) < 0Where does f(x) = x^3 / (x^2−1) have a critical point, which is not an extremum?1.Solve the roots of the equation f(x)=-0.5x^2+2.5x+4.5 a.With the Graphical Method b.Using quadratic formula
- Prove that the equation x^3 + x^2 -1 = 0 has a solution between x = 2/3 and x = 1.3- When calculating the approximate solution of the f(x)=0 equation in the interval [a,b] using the graphical method, which of the following is accepted as the solution?a)The point of the function graph that is closest to the axis. B) The point where the graph of the function cuts the y-axis.NS)The point of the function graph closest to the x-axis. D)The point of the function graph that is equidistant from the x and y axes. TO)The point where the graph of the function intersects the x-axis.Find a solution of by fixed point method for f(x)=x^3+x-1=0 ?