A car traveling at 48 ft/sec decelerates at a constant 3 feet per second squared. How many feet does the car travel before coming to a complete stop?

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter12: Quadratic Functions
Section12.6: Solving Problems Involving Quadratic Equations
Problem 1.1E
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A car traveling at 48 ft/sec decelerates at a constant 3 feet per second squared. How many feet does the car travel before coming to a complete stop?
Transcribed Image Text:A car traveling at 48 ft/sec decelerates at a constant 3 feet per second squared. How many feet does the car travel before coming to a complete stop?
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v = u+atu = 48a= -3      [decelerating value]v=0           [complete stop]Hence,t= v-uat= 0-48-3t= 483t=16 seconds

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