A car with good tire tread can stop in less distance than a car with poor tread. The formula for the stopping distance d, in feet, of a car with good tread on dry cement is approximated byd = 0.04v2 + 0.5v,where v is the speed of the car. If the driver must be able to stop within 45 ft, what is the maximum safe speed, to the nearest mile per hour, of the car?mph

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Asked Nov 24, 2019
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A car with good tire tread can stop in less distance than a car with poor tread. The formula for the stopping distance d, in feet, of a car with good tread on dry cement is approximated by

d = 0.04v2 + 0.5v,

where v is the speed of the car. If the driver must be able to stop within 45 ft, what is the maximum safe speed, to the nearest mile per hour, of the car?
mph

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Consider the given model for car as d = 0.04v2 +0.5v and d = 45 ft The maximum speed of the car is obtained as follows 0.04v20.5v= 45 4v250v 4500 4v250v 4500 0 21225v-2250 0 25t (25)-4(2)(-2250) 2(2)

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Algebra