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A chemist needs 8 liters of a 25% acid solution. The solution is to be mixed from three solutions whose concentrations are 10%, 20%, and 50%. How many liters of each solution will satisfy each condition? (a) Use 2 liters of the 50% solution. 10% solution 2 20% solution 4. L. (b) Use as little as possible of the 50% solution. 10% solution L 20% solution X L 50% solution L. (c) Use as much as possible of the 50% solution. 10% solution 20% solution 50% solution 3 L

A chemist needs 8 liters of a 25% acid solution. The solution is to be mixed from three solutions whose concentrations are 10%, 20%, and 50%. How many liters of each solution will satisfy each condition? (a) Use 2 liters of the 50% solution. 10% solution 2 20% solution 4. L. (b) Use as little as possible of the 50% solution. 10% solution L 20% solution X L 50% solution L. (c) Use as much as possible of the 50% solution. 10% solution 20% solution 50% solution 3 L

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.6: Applications And The Perron-frobenius Theorem
Problem 65EQ
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A chemist needs 8 liters of a 25% acid solution. The solution is to be mixed from three solutions whose concentrations are 10%, 20%, and 50%. How many liters of each solution will satisfy each condition? (a) Use 2 liters of the 50% solution. 10% solution 2 20% solution 4 (b) Use as little as possible of the 50% solution. 10% solution 20% solution X L 50% solution X L (c) Use as much as possible of the 50% solution. 10% solution 20% solution 50% solution
Transcribed Image Text:A chemist needs 8 liters of a 25% acid solution. The solution is to be mixed from three solutions whose concentrations are 10%, 20%, and 50%. How many liters of each solution will satisfy each condition? (a) Use 2 liters of the 50% solution. 10% solution 2 20% solution 4 (b) Use as little as possible of the 50% solution. 10% solution 20% solution X L 50% solution X L (c) Use as much as possible of the 50% solution. 10% solution 20% solution 50% solution
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