A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 160 feet per second from an initial height of 74 feet off the ground, then the height of the projectile, h, in feet, t seconds after it's shot is given by the equation: h = - 16t + 160t + 74 Find the two points in time when the object is 114 feet above the ground. Round your answers to the nearest hundredth of a second (two decimal places).

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter4: Polynomials
Section4.8: Rate-time-distance Problems
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A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 160 feet per second
from an initial height of 74 feet off the ground, then the height of the projectile, h, in feet, t seconds after it's shot is given by the
equation:
h =
16t + 160t + 74
Find the two points in time when the object is 114 feet above the ground. Round your answers to the nearest hundredth of a
second (two decimal places).
Transcribed Image Text:A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 160 feet per second from an initial height of 74 feet off the ground, then the height of the projectile, h, in feet, t seconds after it's shot is given by the equation: h = 16t + 160t + 74 Find the two points in time when the object is 114 feet above the ground. Round your answers to the nearest hundredth of a second (two decimal places).
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