A coffee shop currently sells 340 lattes a day at $3.25 each. They recently tried raising the by price by $0.25 a latte, and found that they sold 50 less lattes a day. a) Assume that the number of lattes they sell in a day, N , is linearly related to the sale price, p (in dollars). Find an equation for N as a function of p. N(p) = | b) Revenue (the amount of money the store brings in before costs) can be found by multiplying the cost per cup times the number of cups sold. Again using p as the sales price, use your equation from above to write an equation for the revenue, R as a function of p. R(p) = | C) The store wants to maximize their revenue (make as much money as possible). Find the value of; that will maximize the revenue (round to the nearest cent). which will give a maximum revenue of $

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
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A coffee shop currently sells 340 lattes a day at $3.25 each. They recently tried raising the by price
by $0.25 a latte, and found that they sold 50 less lattes a day.
a) Assume that the number of lattes they sell in a day, N , is linearly related to the sale price, p (in
dollars). Find an equation for N as a function of p.
N(p) =|
b) Revenue (the amount of money the store brings in before costs) can be found by multiplying the
cost per cup times the number of cups sold. Again using p as the sales price, use your equation
from above to write an equation for the revenue, R as a function of p.
R(p)
C) The store wants to maximize their revenue (make as much money as possible). Find the value of p
that will maximize the revenue (round to the nearest cent).
p=
which will give a maximum revenue of $
Transcribed Image Text:A coffee shop currently sells 340 lattes a day at $3.25 each. They recently tried raising the by price by $0.25 a latte, and found that they sold 50 less lattes a day. a) Assume that the number of lattes they sell in a day, N , is linearly related to the sale price, p (in dollars). Find an equation for N as a function of p. N(p) =| b) Revenue (the amount of money the store brings in before costs) can be found by multiplying the cost per cup times the number of cups sold. Again using p as the sales price, use your equation from above to write an equation for the revenue, R as a function of p. R(p) C) The store wants to maximize their revenue (make as much money as possible). Find the value of p that will maximize the revenue (round to the nearest cent). p= which will give a maximum revenue of $
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