SQL HelpA) Using the previous information write the SQL statement creating the Player table. A college football association has a database to record various data about their teams, playersand affiliated university.The following relational model presents the relationship between the tables:TeamTeamIDTeamNameCityStateWinLosPlayerPlayerlDPlayerNameAgePositionTeamIDCollegelDCollegeCollegelDCollegeNameCityStateWe have the following information about the attributes:Team:- TeamID is an integer and is the Primary Key of the Team table- TeamName is a chain of no more than 30 characters- City is a chain of no more than 25 characters- State is a chain of 2 characters- Win is an integer- Loss is an integerPlayer:- PlayerlD is an integer and is the Primary Key of the Player table- PlayerName is a chain of no more than 50 characters- Age is an integer- Position is a chain of no more than 15 characters- TeamID is an integer and is a foreign key of the Player table- CollegelD is an integer and is a foreign key of the Player tableCollege:- CollegelD is an integer and is the Primary Key of the College table- CollegeName is a chain of no more than 30 characters- City is a chain of no more than 25 characters- State is a chain of 2 characters

Question a: create table Team(TeamID int primary key,TeamName varchar(30),City varchar(25),State…

Answered: A college football association has a…

A college football association has a database to record various data about their teams, players and affiliated university. The following relational model presents the relationship between the tables:

Database Systems: Design, Implementation, & Management

12th Edition

ISBN:9781305627482

Author:Carlos Coronel, Steven Morris

Publisher:Carlos Coronel, Steven Morris

Chapter8: Advanced Sql

Section: Chapter Questions

Problem 18RQ

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Consider the following shorthand representation of a relational database used by a book publisher to answer the following questions.BRANCH (BRANCH_NUM, COUNTRY, NUM_EMPLOYEES) WRITER (WRITER_NUM, LAST_NAME, FIRST_NAME, BOOK_NUM) BOOK (BOOK_NUM, TITLE, TYPE, PRICE, WRITER_NUM) INVENTORY (BOOK_NUM, BRANCH_NUM, ON_HAND)2.3 List the number of employees for each branch in South Africa. 2.4 List the book code and title of each book of type “Romance”. 2.5 For each type of book list the type and the average price. 2.6 Find the title for each book written by “Bob Builder”. 2.7 List the name of all books in South Africa written by “Hans Anderson“ 2.8 Count the number of books (AS NumOfBooks) written by each author
Passenger (pid, pbithday, pcity)Station (sid, sname, sxcoord, sycoord)CheckIn (pid, departure_sid, arrive_sid, departure_date, arrive_date)departure_sid reference sid in Stationarrive_sid reference sid in Stationpid references pid in Passenger there are 400 million Passenger, 500 stations, and 20 billion checkIn stored in the schema. For simplicity, assume that every attribute is of size 8 bytes, and the size of each tuple is thus 8*x bytes for a table with x attributes, and that the size of a table is simply the size of a tuple multiplied by the number of tuples (i.e., 100% occupancy and no gaps or space for block metadata). Now consider the following queries: SELECT P.pidFROM Passenger p, CheckIn C, Station SWHERE P.pid = C.pidand C.departure_sid = S.sidand S.sname = "LA"and year(P.pbithday) = 2000and date(C.departure_date) = "2015-12-12" question:1. first join P with C, and then join result with S2. first join S with C, and then join result with PWhich way would be faster for this…
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TRUE OR FALSE In the Relational Data Model, Referential Integrity Constraint is a special kind/case of Foreign Key Constraint. Multiple Inheritance happens when a class has more than one sub-class. This problem can be observed in Programming Languages as well. Given two relations named A and B, if we q-JOIN A and B, the maximum number of attributes in the result relation could be (the number of attributes of A) times(*) the number of attributes of B). * in an SQL SELECT statement means “all the tuples”. In relational algebra, Cartesian Product (X) can be implemented using the q-JOIN operator. Cartesian Product ISA q-JOIN where q-condition always evaluates to true. SQL is based on Predicate Calculus. A query in SQL always specifies what should be included in the query result.
This question is related to the Database:- Suppose you are creating a database for a library management system. Explain how you would make a table for the "books" entity and insert some sample data, and then alter the table to add a new column for the "authorID" attribute and update "authorID" with some data. Finally, make a SQL query to retrieve all the books that were published after the year 2000. Note that this book schema has several columns, including "book_id" as the primary key, "title", "authorN", "publisher", "publication_year", "isbn", "language", and "num_pages". It also includes "available" column that is set to "true" by default and can be used to track the availability of the book. Please don't use handwriting...
The following is a relational schema for a database to document sharksightings for a research project. Primary keys are underlined. ForeignKeys are identified by FK, and their name indicates the attribute that theyreference.________________________________________________________________Sharks(shark_id:Integer, name:String, species_name:String,tagged_by_mission_id:Integer (FK))Sightings(shark_id:Integer (FK), sighting_num:Integer,sight_time:Timestamp, lat:Real, lng:Real, ocean:String, mission_id:Integer(FK))Missions(mission_id:Integer, start_date:Date, end_date:Date,vessel_id:Integer (FK))ResearchVessels(vessel_id:Integer, name:String)________________________________________________________________Sharks identified by a unique id, have a name which is not necessarilyunique, and a scientific species name.All Sharks are tagged and are sighted by Research Vessels, which areresearch ships that go on research Missions throughout the year. EachMission has a start and end date. Shark…
Consider the relational database below, where the primary keys are underlined.employee (person-name, street, city)works (person-name, company-name, salary)company (company-name, city)manages (person-name, manager-name)Give a query for each of the following:a Give all managers in database a 10 percent raise.b Give managers in the database a 10 percent raise, unless the salary would be greaterthan $100,000. In such cases, give only 3 percent raise.c Delete all tuples in the works relation for employees of Small Bank Corporation
25. In the relational model, relationships between relations or tables are created by using: a. composite keys b. determinants c. candidate keys d. foreign keys
Let us consider the following relational database. Students(stuID, lastName, firstName, major, gpa) Faculty(facID, name, deptName, rank) Classes(classNhmber, facID, schedule, room) Enrolls(stuID, classNumber, grade) The primary keys are underlined. The referential integrity constraints are as follows: The column facID of relation Classes that references table Faculty, The column of stuID of relation Enrolls that references table Students, and The column classNumber of relation Enrolls that references table Classes. The following SQL statement is intended to define the table Students. However, this statement does not work correctly. CREAT TABLE Students( lastName VARCHAR(20), firstName VARCHAR(20), major VARCHAR(40) gpa DECIMAL(3,2), PRIMARY KEY(stuID)); However, this statement does not work correctly. Briefly explain why and list the corrected SQL statement.
Question#2: Given the following Theatre Database form: No.of seats:500 Owner: J.Martin Year Founded: 1890 Owner’s Phone: 2347756 Play Name Play Type No. of performances Play Author name Play Author nationality MacBeth Tragedy 35 W.shakesper English Ulysses Drama 12 J.Joyce Irish Represent the above as an unnormalized relational schema then apply the rules of normalization to normalize it to 3NF.

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