A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium divides into two cells every 20 minutes. The initial population of a is 79 cells. (a) Find the relative growth rate. (Assume t is measured in hours.) k = In(8) (b) Find an expression for the number of cells after t hours. P(t) = 79e' In(8) (c) Find the number of cells after 8 hours. 1325400064 cells (d) Find the rate of growth after 8 hours. (Round your answer to three decimal places.) billion cells per hour (e) When will the population reach 20 000 celle? (D. decimal places
A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium divides into two cells every 20 minutes. The initial population of a is 79 cells. (a) Find the relative growth rate. (Assume t is measured in hours.) k = In(8) (b) Find an expression for the number of cells after t hours. P(t) = 79e' In(8) (c) Find the number of cells after 8 hours. 1325400064 cells (d) Find the rate of growth after 8 hours. (Round your answer to three decimal places.) billion cells per hour (e) When will the population reach 20 000 celle? (D. decimal places
Chapter6: Exponential And Logarithmic Functions
Section6.1: Exponential Functions
Problem 61SE: The fox population in a certain region has an annualgrowth rate of 9 per year. In the year 2012,...
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Can you answer part d, please?
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