A company has $8,650 available per month for advertising. Newspaper ads cost $240 each and can't run more than 25 times per month. Radio ads cost $310 each and can't run more than 35 times per month at this price. Each newspaper ad reaches 5800 potential customers, and each radio ad reaches 6950 potential customers. The company wants to maximize the number of ad exposures to potential customers. Use n for number of Newspaper advertisements and r for number of Radio advertisements . Maximize P = 5800n + 6950r subject to < 25 n < 35 240n + 310r < $8, 650 Enter the solution below. If needed, round ads to 1 decimal palace and group exposure to the nearest whole person. Number of Newspaper ads to run is 25 Number of Radio ads to run is 8.5 Maximum target group exposure is 204905 X people
A company has $8,650 available per month for advertising. Newspaper ads cost $240 each and can't run more than 25 times per month. Radio ads cost $310 each and can't run more than 35 times per month at this price. Each newspaper ad reaches 5800 potential customers, and each radio ad reaches 6950 potential customers. The company wants to maximize the number of ad exposures to potential customers. Use n for number of Newspaper advertisements and r for number of Radio advertisements . Maximize P = 5800n + 6950r subject to < 25 n < 35 240n + 310r < $8, 650 Enter the solution below. If needed, round ads to 1 decimal palace and group exposure to the nearest whole person. Number of Newspaper ads to run is 25 Number of Radio ads to run is 8.5 Maximum target group exposure is 204905 X people
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Functions
Section8.CR: Review Problem Set
Problem 50CR
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