A computer maker receives parts from three suppliers, S1, S2, and S3. 50% come from S1, 20% from S2, and 30% from S3. Among all the parts supplied by S1,5% are defective. For S2 and S3, the portion of defective parts is 3% and 6%,respectively Let D = defective part, then P (D|S2) is %3D
A computer maker receives parts from three suppliers, S1, S2, and S3. 50% come from S1, 20% from S2, and 30% from S3. Among all the parts supplied by S1,5% are defective. For S2 and S3, the portion of defective parts is 3% and 6%,respectively Let D = defective part, then P (D|S2) is %3D
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:A computer maker receives parts from three suppliers,
S1, S2, and S3. 50% come from S1, 20% from S2,
and 30% from S3. Among all the parts supplied by S1,5%
are defective. For S2 and S3, the portion of defective
.parts is 3% and 6%,respectively
Let D =defective part, then P (D|S2) is
Transcribed Image Text:Given that: P(AN B) = 0.15, P(B) = 0.3 and P(A)=0.2
%3D
%3D
Then
:P(A N B) is
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