A concrete column has diameter 4 300 mm. The Column has G 84eek a

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter11: Columns
Section: Chapter Questions
Problem 11.9.8P: Determine the allowable axial load Pallowfor a steel pipe column with pinned ends having an outside...
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Topic: Statistically indeterminate members

Situation #2
A concrete co lumn has a
diameter 4 300 mm. The
column has 6 6teel
rinforcing bars. Each
renforcing bar has a
crocs-sectiomal area 4
J0o mm2. The column is
I150m lorg and has a
load 17 1,370 kn applied
to a
igid steel plati
af the top y the column.
The plati distributes
the load evenly over the
4 the co lumn.)
tumn)
top
E,- 300 GPa ard Ec=arGPa
Find the sfress in the
&feel ard in the concrete
ard the defomation
urder the load.
Transcribed Image Text:Situation #2 A concrete co lumn has a diameter 4 300 mm. The column has 6 6teel rinforcing bars. Each renforcing bar has a crocs-sectiomal area 4 J0o mm2. The column is I150m lorg and has a load 17 1,370 kn applied to a igid steel plati af the top y the column. The plati distributes the load evenly over the 4 the co lumn.) tumn) top E,- 300 GPa ard Ec=arGPa Find the sfress in the &feel ard in the concrete ard the defomation urder the load.
Statically Indetermina
Sanple Problem #1
G sfeel bar omm ir aiameter ard am /rg
is sumounded by a shele 4 cast iron Smm
thick. Fird the Cord that WVicompress
the combined bar a frtal 4 Imm in the
angth 4 am. For steel, Es= 200 GPa ard
for cast irom, Eci= /00 GPa.
Figure
7 (50)"
1963-500mm
5omm,
Smm
4
Aci
1963.50
4
Ac = 863. 94o mm JNETT
From O
As E,
Pi (a)
1963-5(200/0
=196.350 kn
JUAT
Reg'd.
Se, - PaLe,
Acı Eci
Solution
S = Se, =1 -O
ZFu =0
P, + Per = P aO
863.94 (I)10"
Pei = 43.197cn
From
O -239.547
%3D
Transcribed Image Text:Statically Indetermina Sanple Problem #1 G sfeel bar omm ir aiameter ard am /rg is sumounded by a shele 4 cast iron Smm thick. Fird the Cord that WVicompress the combined bar a frtal 4 Imm in the angth 4 am. For steel, Es= 200 GPa ard for cast irom, Eci= /00 GPa. Figure 7 (50)" 1963-500mm 5omm, Smm 4 Aci 1963.50 4 Ac = 863. 94o mm JNETT From O As E, Pi (a) 1963-5(200/0 =196.350 kn JUAT Reg'd. Se, - PaLe, Acı Eci Solution S = Se, =1 -O ZFu =0 P, + Per = P aO 863.94 (I)10" Pei = 43.197cn From O -239.547 %3D
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