A constant force of 50 lb is applied at an angle of 48° to pull a handcart 41 ft across the ground. What is the work done by this force (to 2 decimal places)? Work = 50 lb 48° 41 ft ft-lb

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A: As per the company rule we can answer only first question and rest can be reposted.

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A: r ( t ) = 14t + 1i + 1tj