A container of water has been outdoors in cold weather until a 5.0-cm thick slab of ice has formed on its surface. The air above the ice is at -10°C. kice = 1.7 W/m-K Pice = 0.92 g/cm³ Leice = 333 kJ/kg Data: Assume that the walls of the container are Calculate the rate of formation of ice (in cm/hr) on the bottom surface of the slab. thermally insulating.
A container of water has been outdoors in cold weather until a 5.0-cm thick slab of ice has formed on its surface. The air above the ice is at -10°C. kice = 1.7 W/m-K Pice = 0.92 g/cm³ Leice = 333 kJ/kg Data: Assume that the walls of the container are Calculate the rate of formation of ice (in cm/hr) on the bottom surface of the slab. thermally insulating.
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![A container of water has been outdoors in cold
weather until a 5.0-cm thick slab of ice has
formed on its surface. The air above the ice is
Data:
kice = 1.7 W/m-K
Pice = 0.92 g/cm³
Le,ice = 333 kJ/kg
%3D
at -10°C.
Assume that the walls of the container are
Calculate the rate of formation of ice (in
cm/hr) on the bottom surface of the slab.
thermally insulating.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd671e1e8-91b8-4752-9ea9-0a2276dfebef%2F8f1784f0-214e-46f6-b4f5-6b235ee851eb%2F7hbhk9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A container of water has been outdoors in cold
weather until a 5.0-cm thick slab of ice has
formed on its surface. The air above the ice is
Data:
kice = 1.7 W/m-K
Pice = 0.92 g/cm³
Le,ice = 333 kJ/kg
%3D
at -10°C.
Assume that the walls of the container are
Calculate the rate of formation of ice (in
cm/hr) on the bottom surface of the slab.
thermally insulating.
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Step 1
Given
Thickness (y) = 5.0 cm = 0.05 m
Temperature = ( Temperature difference
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