A container of water has been outdoors in cold weather until a 5.0-cm thick slab of ice has formed on its surface. The air above the ice is at -10°C. kice = 1.7 W/m-K Pice = 0.92 g/cm³ Leice = 333 kJ/kg Data: Assume that the walls of the container are Calculate the rate of formation of ice (in cm/hr) on the bottom surface of the slab. thermally insulating.

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A container of water has been outdoors in cold
weather until a 5.0-cm thick slab of ice has
formed on its surface. The air above the ice is
Data:
kice = 1.7 W/m-K
Pice = 0.92 g/cm³
Le,ice = 333 kJ/kg
%3D
at -10°C.
Assume that the walls of the container are
Calculate the rate of formation of ice (in
cm/hr) on the bottom surface of the slab.
thermally insulating.
Transcribed Image Text:A container of water has been outdoors in cold weather until a 5.0-cm thick slab of ice has formed on its surface. The air above the ice is Data: kice = 1.7 W/m-K Pice = 0.92 g/cm³ Le,ice = 333 kJ/kg %3D at -10°C. Assume that the walls of the container are Calculate the rate of formation of ice (in cm/hr) on the bottom surface of the slab. thermally insulating.
Expert Solution
Step 1

Given

Thickness (y)         = 5.0 cm  = 0.05 m

Temperature θ   = -10°C  ( Temperature difference θ = 0°--10°) = 10° C

kice                         = 1.7 W/m.Kρice                        = 0.92 g/cm3 = 920 kg/m3Lf,ice                         =  333 kJ/kg  =333×1000  J/kg

 

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