A continuous tunction y=f(x) is known to be negative atx=2 and positive at x=6. Why does the equation f(x) =0 have at least one solution between x=2 and x=6? Hlustrate with a sketch. Why does the equation fx) =0 have at least one solution between x=2 and x=6? OA )=0 has at least one solution bebween x=2 and x=6 because f(x) must pass through all values between f(2) and f(8). regardless of whether f is continuous, OB. f)=0 has at least one solution between x=2 and x=6 because all continuous functions have at least one zero over any nonempty closed interval. OC fix) =0 has at least one solution between x2 and x=6 becausef is a continuous function on the closed interval [2, 6j, and if yo is any value between f(2) and f(0). then yo =f(c) for some c in [2. 6). Choose a graph below that ustrates the situation. OA OB. Oc. OD.
A continuous tunction y=f(x) is known to be negative atx=2 and positive at x=6. Why does the equation f(x) =0 have at least one solution between x=2 and x=6? Hlustrate with a sketch. Why does the equation fx) =0 have at least one solution between x=2 and x=6? OA )=0 has at least one solution bebween x=2 and x=6 because f(x) must pass through all values between f(2) and f(8). regardless of whether f is continuous, OB. f)=0 has at least one solution between x=2 and x=6 because all continuous functions have at least one zero over any nonempty closed interval. OC fix) =0 has at least one solution between x2 and x=6 becausef is a continuous function on the closed interval [2, 6j, and if yo is any value between f(2) and f(0). then yo =f(c) for some c in [2. 6). Choose a graph below that ustrates the situation. OA OB. Oc. OD.
Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter2: Functions
Section2.4: Average Rate Of Change Of A Function
Problem 4.2E: bThe average rate of change of the linear function f(x)=3x+5 between any two points is ________.
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![A continuous function y=f(x) is known to be negative at x=2 and positive at x -6. Why does the equation f(x)=0 have at least one solution between x= 2 and x-6? Illustrate with a sketch.
Why does the equation f(x)=0 have at least one solution between x-2 and x-6?
OA f(x)=D0 has at least one solution between x 2 andx-6 because f(x) must pass through all values between f(2) and f(6), regardless of whether f is continuouUS.
OB. f(x)-D0 has at least one solution between x=2 and x 6 because all continuous functions have at least one zero over any nonempty closed interval.
OC. f(x)3D0 has at least one solution between x 2 andx-6 because f is a continuous function on the closed interval [2, 6], and if yo is any value between f(2) and f(6), then yo = f(c) for some c in [2, 6].
Choose a graph below that illustrates the situation.
O A
O B.
Oc.
OD.
IA
10
Click to select your answer.
3=
O 4)
10/
9 Type here to search
F8
F10
F11
Insert
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Transcribed Image Text:A continuous function y=f(x) is known to be negative at x=2 and positive at x -6. Why does the equation f(x)=0 have at least one solution between x= 2 and x-6? Illustrate with a sketch.
Why does the equation f(x)=0 have at least one solution between x-2 and x-6?
OA f(x)=D0 has at least one solution between x 2 andx-6 because f(x) must pass through all values between f(2) and f(6), regardless of whether f is continuouUS.
OB. f(x)-D0 has at least one solution between x=2 and x 6 because all continuous functions have at least one zero over any nonempty closed interval.
OC. f(x)3D0 has at least one solution between x 2 andx-6 because f is a continuous function on the closed interval [2, 6], and if yo is any value between f(2) and f(6), then yo = f(c) for some c in [2, 6].
Choose a graph below that illustrates the situation.
O A
O B.
Oc.
OD.
IA
10
Click to select your answer.
3=
O 4)
10/
9 Type here to search
F8
F10
F11
Insert
&
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