A cube with 20-cm-long sides is sitting on the bottom of an aquarium in which the water is one meter deep. Set-up the integral for the force on one of the sides of the cube. 3920 f*(1-y)day 3920 of 5 (1-y)dy 0 1960 of (1-y)dy 1960 f¹/5(1-y)dy

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A: Note : As per our guidelines we are supposed to answer only first 3 subparts if there are multiple…

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A: The integral is  ∫ dxxx-1=∫f(y)dy

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A: fristly given curve are simplyfy and diagram curve then use for shell method

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Q: 5. Evaluate the integral 2 c2x x2 (x² + 2y³) dy dx.

A: As per bartleby guidelines we are supposed to answer only one question per post. This post contains…

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A: Form the graph first then see maxima and minima

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A: Please re-upload the other two questions.

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A: We can solve this as follows:

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A: To find out the integration.

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A: As equation is an homogeneous differential equation then put y =vx and solve.

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A: Answer: The solution is as given below:

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A: let the height of tank be "h"Volume is given by VdVdt=0.1 cu. ft/hrh=2 ftV= 10 cu. ftdhdt=?

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A: This question can be solved using the concept of area under curves.

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A: This question is based on indefinite integral using partial fraction.

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Q: 8 9 Suppose that f is integrable, and that f(z)dz = 5 and [f(z)dz = 10. Find the value of the…

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