A cylindrical can, open on top, is to hold 355 cubic centimeters of liquid. Find the height and radius that minimizes the amount of material needed to manufacture the can. (These are metric units, so the answer will be in centimeters with 2.54cm=1in.)

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How big is that can?
A cylindrical can, open on top, is to hold 355 cubic centimeters of liquid. Find the height and radius that minimizes the amount of
material needed to manufacture the can. (These are metric units, so the answer will be in centimeters with 2.54cm=lin.)
(a) The volume of the can follows which formula (using r for the radius of the can and h for the height)?
OV = 27 · r .h
OV = T: p2 . h
OV = T- p2 . h?
OV = 27 · r2. h
(b) The surface area of the can follows which formula (using r for the radius of the can and h for the height)?
OSA = 27 · r · h
OSA = T· r2 . h
OSA = 27 · r ·h + a · r²
O SA = 2T :r :
- h + 2ñ · r²
(c) Illustrate how this is done. Show the commands to find the height and the radius.
Transcribed Image Text:How big is that can? A cylindrical can, open on top, is to hold 355 cubic centimeters of liquid. Find the height and radius that minimizes the amount of material needed to manufacture the can. (These are metric units, so the answer will be in centimeters with 2.54cm=lin.) (a) The volume of the can follows which formula (using r for the radius of the can and h for the height)? OV = 27 · r .h OV = T: p2 . h OV = T- p2 . h? OV = 27 · r2. h (b) The surface area of the can follows which formula (using r for the radius of the can and h for the height)? OSA = 27 · r · h OSA = T· r2 . h OSA = 27 · r ·h + a · r² O SA = 2T :r : - h + 2ñ · r² (c) Illustrate how this is done. Show the commands to find the height and the radius.
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