A diverging lens of focal length -12.4 cm is placed 40.0 cm from a converging lens of unknown focal length. A 15.2 cm tall erect object is placed 25.3 cm in front of the diverging lens which is to produce an image on a screen that is twice the size of the original object but inverted.
A diverging lens of focal length -12.4 cm is placed 40.0 cm from a converging lens of unknown focal length. A 15.2 cm tall erect object is placed 25.3 cm in front of the diverging lens which is to produce an image on a screen that is twice the size of the original object but inverted.
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A diverging lens of focal length -12.4 cm is
placed 40.0 cm from a converging lens of
unknown focal length. A 15.2 cm tall erect
object is placed 25.3 cm in front of the
diverging lens which is to produce an
image on a screen that is twice the size of
the original object but inverted.
• Where should the screen be located
to produce a clear image?
• What is the focal length of the
converging lens?
What is the height of the
intermediate image formed by the
diverging lens
If the screen is removed and the
image is viewed using your eyes
instead, what angular magnification
would result from placing your eyes
40 cm from the final image?
Plz draw the picture and write down the
detail. Thanks a lot !!!
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