A doctor is called to see a sick child. In the neighborhood is known that:80% of sick children have flu, and 20% of sick children have measles, so that P(F)=D0.80 andP(M)=0.20Let F = event of a child being sick with flu; M = event of a child being sick with measles.%3D%3DAssume for simplicity that there no other sickness among in that neighborhood, besides flu andmeasles. A well-known symptom of measles is a rash (the event of having which we denote R).Assume that the probability of having a rash if one has measles is P(R | M) = 0.95. However,occasionally children with flu also develop rash, and the probability of having a rash if one has fluis P(R | F) = 0.08. Upon examining the child, the doctor finds a rash. What is the probability thatthe child has measles?O 0.2540O 0.8O 0.95O 0.7480

Given Information: PF=0.80 PM=0.20 PR | M=0.95 PR | F=0.08

Answered: A doctor is called to see a sick child.…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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