(a) Find the slope of the curve y = x - 4x -5 at the point P(3, - 8) by finding the limit of the secant slopes through point P. (b) Find an equation of the tangent line to the curve at P(3, -8). (a) The slope of the curve at P(3, -8) is (Simplify your answer.)
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A: Please refer the attached image for complete solution. THANK YOU.
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- Does a Limiting Value Occur? A rocket ship is flying away from Earth at a constant velocity, and it continues on its course indefinitely. Let D(t) denote its distance from Earth after t years of travel. Do you expect that D has a limiting value?Find the slope of the curve y=x2-5x-4 at the point P(3,-10) by finding the limit of the secant slopes through point P. Can you please show me how to solve?FIND THE DERIVATIVE OF THE FUNCTION BY THE LIMIT PROCESS. SHOW YOUR STEP BY STEP SOLUTIONS. 1. f(x)=7 2. g(x)=-3 3. f(x)=-10x
- Draw the curve if y' is negative and y'' is positive on the interval of (2,3), while y' is positive and y'' is positive on the interval of (3, infinity). The vertical asymptote is x=4 while the slant asymptote is y=x+3find the derivative of f(x) = x-3/3x+4 using the limit definition of the derivative. then state the domains of the function and its derivative. must show all stepsThe curve enters the window in the second quadrant, goes down and right, and exits the window nearly vertical at the approximate point (−7.2, −3). The curve reenters the window nearly vertical at the approximate point (−6.7, −3), goes up and right becoming less steep, crosses the x-axis at x = −5, goes up and right becoming more steep, and exits the window at the point (−3.3, 3). The curve reenters the window nearly vertical at the approximate point (−2.9, 3), goes down and right, changes direction at the approximate point (−1.5, 0.5), goes up and right, and exits the window nearly vertical at the approximate point (−0.1, 3). The curve reenters the window nearly vertical at the approximate point (0.2, 3), goes down and right, changes direction at the approximate point (1.6, −2), goes up and right, changes direction at the approximate point (4.3, 2.7), goes down and right, and exits the window nearly vertical at the approximate point (5.8, −3). The curve reenters the window nearly…
- f(x)=x2+2x-1 g(x)= -500/x, x ≠0 k(x)= |x-2| For each function, do the following: Compute the derivative (that is, the derivative function) by evaluating the limit, for example, lim h →0 f(x+h)− f(x)/h. Show your work. (Notice that for the function k(x), you’ll have to compute the limit differently depending on whether x < 2 or x > 2, and you’ll end up with a piecewise function for the derivative. Since the graph of k(x) is made of straight lines, you can also find its derivative by looking at the actual slopes.)The tangent line to the graph of f(x) at x = 2 is shown. On the tangent line, P is the point of tangency and A is another point on the line. The x y-coordinate plane is given. There is 1 curve and 1 line on the graph. The curve enters the window in the second quadrant, goes down and right becoming less steep, passes through the point (−1, 2.5) crossing the line, crosses the y-axis at approximately y = 1.3, becomes nearly horizontal at the approximate point (1, 1.2), goes down and right becoming more steep, passes through the point (2, 1) touching the line, crosses the x-axis at approximately x = 2.9, and exits the window in the fourth quadrant. The line enters the window in the second quadrant, goes down and right, passes through the point (−1, 2.5) crossing the curve, crosses the y-axis at y = 2, passes through the point (2, 1) touching the curve, crosses the x-axis at x = 4, and exits the window in the fourth quadrant. Point P occurs at (2, 1). Point A occurs at (−2, 3). (a)…Use limits to determine the equations for all vertical asymptote. y=(x2-x-2)/(x2-2x+1)
- The total cost and the total revenue (in dollars) for the production and sale of x ski jackets are given by C(x)=28x+37,960 and R(x)=200x−0.1x2 for 0≤x≤2000. (A) Find the value of x where the graph of R(x) has a horizontal tangent line. (B) Find the profit function P(x). (C) Find the value of x where the graph of P(x) has a horizontal tangent line. (D) Graph C(x), R(x), and P(x) on the same coordinate system for 0≤x≤2000. Find the break-even points. Find the x-intercepts of the graph of P(x).Use the limit definition to find the slope of the tangent line to the graph of f at the given point. f(x) = 11 − x2, (2, 7)lim h--->0 (f(2+h)-f(2)) / h , where f(x)=4x+8