(a) For a reaction A + B → P, the rate is given by Rate = k[A] [B]2(i) How is the rate of reaction affected if the concentration of B is doubled?(ii) What is the overall order of reaction if A is present in large excess?(b) A first order reaction takes 30 minutes for 50% completion. Calculate the time required for 90% completion of this reaction. (log 2 = 0.3010)

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(a) For a reaction A + B → P, the rate is given by Rate = k[A] [B]2
(i) How is the rate of reaction affected if the concentration of B is doubled?
(ii) What is the overall order of reaction if A is present in large excess?
(b) A first order reaction takes 30 minutes for 50% completion. Calculate the time required for 90% completion of this reaction. (log 2 = 0.3010)

Expert Solution
Step 1

Given,

rate of reaction, R = kAB2

where, [A] is the concentration of A, and [b] is the concentration of B, k is constant.

Now,

 

i)

concentration of B is doubled, 

[B'] = [2B]

So new rate will be,

R' = kAB'2R' = kA2B2R'=4R

Step 2

ii)

A is present in large excess

If A is present in large excess, then rate will independent of A, that is new rate of reaction will be,

R"=kB2

So, the order of rate is 2

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