A frame ABC is supported in part by cable DBE that passes through a frictionless ring at B. Knowing that the tension in the cable is 385 N, determine (a)- the resultant ( R) of the forces as a vector which exerted by the cables on the support at D and E, (b)- the angles between R and each of the coordinate axes.
A frame ABC is supported in part by cable DBE that passes through a frictionless ring at B. Knowing that the tension in the cable is 385 N, determine (a)- the resultant ( R) of the forces as a vector which exerted by the cables on the support at D and E, (b)- the angles between R and each of the coordinate axes.
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![H.W:
A frame ABC is supported in part by cable DBE that passes through a frictionless ring at B. Knowing that the
tension in the cable is 385 N, determine (a)- the resultant ( R ) of the forces as a vector which exerted by the
cables on the support at D and E, (b)- the angles between R
and each of the coordinate axes.
Answer:
280 mm
210 mm
R= FRD + FRE =-(375 N)i + (455 N)j-(460 N)k
E
0 = 120.1°
= 52.5°
510 mm
400 mm
0. = 128.0°
600 mm
480 mm
B.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6b1cd052-3ef6-413f-91af-7b7c6c662a6c%2F8791bba1-98be-47be-98da-dc8b877b8b22%2Ft93j87f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:H.W:
A frame ABC is supported in part by cable DBE that passes through a frictionless ring at B. Knowing that the
tension in the cable is 385 N, determine (a)- the resultant ( R ) of the forces as a vector which exerted by the
cables on the support at D and E, (b)- the angles between R
and each of the coordinate axes.
Answer:
280 mm
210 mm
R= FRD + FRE =-(375 N)i + (455 N)j-(460 N)k
E
0 = 120.1°
= 52.5°
510 mm
400 mm
0. = 128.0°
600 mm
480 mm
B.
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