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(a) Graph r = 1/(2 cos 0) for –x/2 sosa/2 and r =1. Then write an iterated integral in polar coordinates representing the area inside the curve r = 1 and to the right of r = 1/(2 cos ®). (Use t for 0 in your work.) With a = ,b= c= and d = area = (b) Evaluate your integral to find the area. area =

(a) Graph r = 1/(2 cos 0) for –x/2 sosa/2 and r =1. Then write an iterated integral in polar coordinates representing the area inside the curve r = 1 and to the right of r = 1/(2 cos ®). (Use t for 0 in your work.) With a = ,b= c= and d = area = (b) Evaluate your integral to find the area. area =

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.6: Additional Trigonometric Graphs
Problem 67E
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(a) Graph r = 1/(2 cos 0) for -T/2<0<T/2 and r = 1. Then write an iterated integral in polar coordinates representing the area inside the curve r = 1 and to the right of r =1/(2 cos 0). (Use t for 0 in your work.) With a = , b = C = , and d = area = d d (b) Evaluate your integral to find the area. area =
Transcribed Image Text:(a) Graph r = 1/(2 cos 0) for -T/2<0<T/2 and r = 1. Then write an iterated integral in polar coordinates representing the area inside the curve r = 1 and to the right of r =1/(2 cos 0). (Use t for 0 in your work.) With a = , b = C = , and d = area = d d (b) Evaluate your integral to find the area. area =
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