A graphing calculator is recommended. Use the Squeeze Theorem to show that lim x² cos(237x) = 0. X-0 Illustrate by graphing the functions f(x) = -x², g(x) = x² cos(23x), and h(x) = x² on the same screen.

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter4: Calculating The Derivative
Section4.2: Derivatives Of Products And Quotients
Problem 35E
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I need help solving this Calculus question - Limits and Derivatives type

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A graphing calculator is recommended.
Use the Squeeze Theorem to show that lim x² cos(23лx) = 0.
X→0
Illustrate by graphing the functions f(x) = -x², g(x) = x² cos(23πx), and h(x) = x² on the same screen.
✓≤ x² сos(23πx) < ?
Let f(x) = -x², g(x) = x² cos(237x), and h(x) = x². Then ? ✓ ≤ cos(23πx) ≤ ? ✓
lim_g(x) =
X→0
?
✓. Since lim f(x) = lim h(x) = |
x → 0
x →0
, by the Squeeze Theorem we have
Transcribed Image Text:A graphing calculator is recommended. Use the Squeeze Theorem to show that lim x² cos(23лx) = 0. X→0 Illustrate by graphing the functions f(x) = -x², g(x) = x² cos(23πx), and h(x) = x² on the same screen. ✓≤ x² сos(23πx) < ? Let f(x) = -x², g(x) = x² cos(237x), and h(x) = x². Then ? ✓ ≤ cos(23πx) ≤ ? ✓ lim_g(x) = X→0 ? ✓. Since lim f(x) = lim h(x) = | x → 0 x →0 , by the Squeeze Theorem we have
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