A hydrogen atom emits light and ends in a state characterized by n₂ = 2. If the wavelength of the light emitted is 434 nm, use the Rydberg formula below to find the value of n₁ that characterizes the initial state of the atom. (RH= 1.09737316 × 107 m-1) 1 -=R₁ 2 H n -

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A hydrogen atom emits light and ends in a state characterized by n₂ = 2. If the wavelength of the light emitted is 434
nm, use the Rydberg formula below to find the value of n₁ that characterizes the initial state of the atom. (RH=
1.09737316 × 107 m-1)
(3)
H
2
2
n
n
2
1
-=R
2
Transcribed Image Text:A hydrogen atom emits light and ends in a state characterized by n₂ = 2. If the wavelength of the light emitted is 434 nm, use the Rydberg formula below to find the value of n₁ that characterizes the initial state of the atom. (RH= 1.09737316 × 107 m-1) (3) H 2 2 n n 2 1 -=R 2
Expert Solution
Step 1

we have n2 = 2 

λ=434nm = 434×10-9m

RH = 1.09737316×107 m-1 

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