(a) If a > 0, find the area of the surface generated by rotating the loop of the curve 3ay = x(a – x) about the x-axis. (а—Зх) 2/3ax (b) Find the surface area if the loop is rotated about the y-axis. na“ 3

Intermediate Algebra
10th Edition
ISBN:9781285195728
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Conic Sections
Section8.2: More Parabolas And Some Circles
Problem 63.2PS: By expanding (xh)2+(yk)2=r2, we obtain x22hx+h22ky+k2r2=0. When we compare this result to the form...
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We have the following.
y
3 a y = x (a – x)?
X
a
(a) If a > 0, find the area of the surface generated by rotating the loop of the curve 3ay = x(a – x)² about the x-axis.
(а-3x)
2v 3ax
(b) Find the surface area if the loop is rotated about the y-axis.
2
na
3
Transcribed Image Text:We have the following. y 3 a y = x (a – x)? X a (a) If a > 0, find the area of the surface generated by rotating the loop of the curve 3ay = x(a – x)² about the x-axis. (а-3x) 2v 3ax (b) Find the surface area if the loop is rotated about the y-axis. 2 na 3
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