a) In pedigree B What fraction of polydactylous female is in generation iii?b) for pedigree A, describe the phynotype of male and female children in generation ii. The following pedigrees illustrate the inheritance of albinism (inability to make the skinpigment melanin) and polydactyly (extra fingers and toes).OJoseph CeciliaMoses JenniferO11Don Lani Jane Sarah TomNigel Rita Peter KilaMary11LloydSam Elizabeth AnnJohn Simon Jane AnnO Normal femaleAlbino femaleNormal femalePolydactylous femaleNormal maleAlbino maleNormal malePolydactylous maleAlbinismPolydactylyPedigrees showing inheritance of albinism and polydactyly.-OREDMI NOTE 8AI QUAD CAMERA

Name: a) In pedigree B What fraction of polydactylous female is in generatio
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: a) In pedigree B What fraction of polydactylous female is in generation iii?b) for pedigree A, describe the phynotype of male and female children in generation ii. The following pedigrees illustrate the inheritance of albinism (inability to make the

The pedigree indicates if the DNA is passed down unchanged from generation to generation. It can…

Answered: a) In pedigree B What fraction of…

Science

Biology

a) In pedigree B What fraction of polydactylous female is in generation iii? b) for pedigree A, describe the phynotype of male and female children in generation ii.

Biology Today and Tomorrow without Physiology (MindTap Course List)

5th Edition

ISBN:9781305117396

Author:Cecie Starr, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Christine Evers, Lisa Starr

Chapter9: Patterns Of Inheritance

Section: Chapter Questions

Problem 13SQ

See similar textbooks

Similar questions

Frank and Susan both have freckles but they're firstborn son Lawrence does not demonstrate the characteristics. What are the most likely genotype of Frank Susan and Lawrence?
Parents Genotype : Bb/bb – Eye Color - (brown eyes dominant , blue eyes recessive) Dd- Dimples ( dominant) Cc/cc- Cleft chin (Dominant) Sarah BbDdcc James bbDdCc What is the probability that Sarah and James will have a baby girl with blue eyes and dimples
Cystic fibrosis is determined by simple dominant-recessive inheritance, where the trait for cystic fibrosis is recessive. Given Rnormal, r is CF gene, complete the following Punnett square
Wilson’s disease is an inherited disorder in which there is too much copper in the body’s tissue. It is inherited in an autosomal recessive manner. Below are pedigrees from two families where some members of a family have Wilson’s disease. Neither Hillary nor Justin have Wilson’s disease. If they have a child, what is the chance this child will have Wilson’s disease?
Bryan has albinism, an autosomal recessive trait, which means he is homozygous recessive for albinism and his genotype is aa. Bryan's parents, Frank and Amy, do not have albinism however they must both be heterozygous. Bryan's sister, Allice, is a carrier for albinism. If Allice has offspring with Jim, who has no family history of albinism, what are the chances that their offspring are carriers for albinism? What are the chances that they children will get albinism? Use Punnett squares.
PEDIGREE ANALYSIS ANA MARRIED JOSE AND HAD THREE CHILDREN, JOSE MIGUEL, MARIA ANA, AND JOSE MANUEL. JOSE, JOSE MIGUEL, AND JOSE MANUEL DISCOVERED THEY HAVE MUSCULAR DYSTROPHY, MD ( A HEREDITARY CONDITION MARKED BY PROGRESSIVE WEAKENING AND WASTING OF THE MUSCLES). JOSE MANUEL MARRIED LEILANI AND HAD TWO CHILDREN, MARIA LUISA AND MARIA LOLITA. MARIA LUISA ALSO HAS MUSCULAR DYSTROPHY AND MARRIED ALFREDO. THEY HAD TWO CHILDREN, JULIE ANN AND JOSE ALFRED. JULIE ANN HAS MUSCULAR DYSTROPHY. DRAW AN ORGANIZED PEDIGREE. LABEL THE PEDIGREE USING ROMAN NUMERALS AND ARABIC NUMERALS. WHEN ASSIGNING THE INDIVIDUAL MEMBERS OF THE CORRECT LABEL, FOLLOW THE SEQUENCE/ORDER AS THE MEMBER IS IDENTIFIED IN THE GIVEN DESCRIPTION ABOVE. INDICATE EACH INDIVIDUAL’S POSSIBLE GENOTYPE. USE THE LETTER M TO REPRESENT THE TRAIT. WRITE THIS BELOW EACH SYMBOL. THEN ANSWER THE QUESTION: IS THE DISEASE AUTOSOMAL OR SEX-LINKED? DOMINANT OR RECESSIVE?
Albinism is a recessive disorder where there is a lack of melanin. Andrea and her husband Claude both have normal skin pigmentation. Andrea’s mother has the albino phenotype, but her father and her brother do not (normal pigmentation). Claude’s parents are both normal, but he has a sister who has the condition (is albino). Answer the following questions Determine the genotypes for Claude, Claude’s parents, and sister. NOTE: Draw a punnet square or show your work.
Parents Genotype : Bb/bb – Eye Color - (brown eyes dominant , blue eyes recessive) Dd- Dimples ( dominant) Cc/cc- Cleft chin (Dominant) Sarah BbDdcc James bbDdCc If they plan to have 4 children, what is the probability of having: all boys with cleft chin?
People with polydactyly have more than five fingers or toes on their hands or feet. Polydactyly results from an autosomal dominant genetic disorder. Draw a pedigree for a family with polydactyly, using the following information: Zack has polydactyly but his wife, Zoe does not. Zack and Zoe’s daughter Yolanda has polydactyly but their son Yogi does not. Yolanda has two children with her husband, Xavier, who does not have polydactyly: Wilma, who is normal and Wade, who has polydactyly. Use your pedigree to determine what is Zoe's genotype. A) DD B)dd C)Dd
Cystic fibrosis is a recessive genetic disorder. Ron is homozygous dominant (FF) and Nancy is a carrier (Ff) of cystic fibrosis. Use a Punnett square to predict the probability that one of their children will have cystic fibrosis?
The given pedigree chart corresponds with generational cystic fibrosis. If individuals III-2 and III-3 were to have a second child, what is the probability that their second child will have cystic fibrosis?
Albinism is a recessive autosomal trait for skin pigmentation. Hemophilia is a sex-linked recessivedisorder of the blood. assign alleles to the traitsA – normal skin pigmentation X H – normal blooda – albino X h - hemophilia A double heterozygous woman marries a non-hemophilic man and heterozygous for skinpigmentation.  Double heterozygous means heterozygous for both traits. Aa for skin pigmentation andX H X h for blood trait. Therefore, the genotype of the woman is AaX H X h .  Non-hemophilic man is X H Y and heterozygous for skin pigmentation is Aa. The genotype,therefore, of the man is AaX H Y. What is the probability that they will have:a. a child with normal skin? _____________________b. a child with normal blood? _____________________c. an albino girl? _____________________d. A hemophilic boy? _____________________