A Jsin(3x)cos(4x)dx = [ sin(7x) – sin(x). A dx 2 * cos(x) – cos(7x) ® Ssin(3x)sin(4x)dx= [co c) All of the above D Jcos(3x)cos(4x)dx = [cos(x) + cos(7x) dx 2 + cos(7x) O Ssin(4x)cos(3x)dx =Scos(x) 2

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A: Follow next step

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A: Option C

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Q: then udu = – xdx.

A: Follow the procedure given below.

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A:

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A: Let's find.

Q: 6 3 х+7

A:

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A: First we put e3x+1=t and differentiate both sides with respect to t and solve it.

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A: fx=2x+3,x&lt;15,x≥1

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A:

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Q: Evaluate: Jy?cos2ydy 글an2y-글ycos2y+ 금snzy+ A 1 1 1 żsin2y-ycos2y-sin2y+C В 4 1 © sin2y+ycos2y+sin2y+…

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Q: 39) (a) Let Ax) = cos(3x – 2). Find f" (x). (153) (b) Let g(x) = 2***. Find g (x).

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A: To write that it is true or false.

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A: Follow the procedure given below.

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A: ∫sin7xcos5x1-sinx21+sinx2dx=∫sin7xcos5xcos2x1+sinx21+sinx2dx=∫sin7xcosxdxLet u=sinx.=∫…

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Q: Question 10 Evaluate: Jevdx.

A: