A large lot in a park is going to be split into two softball fields, and each field will be enclosed with a fence.A rectangular lot, wider in width than it is tall in height, is shown. A vertical line begins about halfway across the top of the rectangle extends down to bottom side, splitting the lot in two.The top side length is labeled y.The left and right side lengths are labeled x, as well as the middle vertical line.The parks and recreation department has 2,700 feet of fencing to enclose the fields. What dimensions will enclose the greatest area?(a)Fill in the following equation.·x + · y = 2,700(b)Solve the equation in part (a) for y.y = + · x(c)UsingA = x · y,write an equation for the area A in terms of x.A = (d)What values of x and y will maximize the area of the enclosures?x = y =(e)What is the maximum area (in square feet)?sq ft

We have to solve various part as given in the question.

Answered: A large lot in a park is going to be…

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A large lot in a park is going to be split into two softball fields, and each field will be enclosed with a fence.

A rectangular lot, wider in width than it is tall in height, is shown. A vertical line begins about halfway across the top of the rectangle extends down to bottom side, splitting the lot in two.
The top side length is labeled y.
The left and right side lengths are labeled x, as well as the middle vertical line.

The parks and recreation department has 2,700 feet of fencing to enclose the fields. What dimensions will enclose the greatest area?

(a)

Fill in the following equation.

·x +

· y = 2,700

(b)

Solve the equation in part (a) for y.

y = +

· x

(c)

Using

A = x · y,