A liquid (SG = 0.8 and μ = 5 cP = 0.00336 lb/ft s) from a solvent recovery plant is being pumped from a vessel into a reactor. The flow rate to the rector is 100 GPM (0.2228 ft/s,) and the line, schedule 40-carbon steel (z = 0.0018 in). The pressure in the vessel is 15 psig and the reactor is pressurized to 65 psig. The flow into the reactor is 25 ft below the level in the vessel as shown in the drawing. The centrifugal pump is located 5 ft below the level in the vessel. a. b. The piping consists of the following: Suction line 10 ft of 2.5" 2 2 1 Pipe Gate valves 90 degree elbows Check valves 2" sch 40 pipe 2.5" Sch 40 pipe Gate valve Check Valve 90° elbows ID=2.067" ID=2.47" K = 8 ft K = 100 fr K = 30 fr Discharge line 325 ft of 2" 2 5 none Acs=0.0233 ft² Acs=0.0332 ft² Determine the velocity in the 2.5" and 2" lines (ft /s). Determine the losses due to friction in both the suction and discharge lines (ft lb/lbm). Estimate the amount of total dynamic head required of the pump (ft lb/lbm) d. If the pump is 80% efficient, determine the work required by the pump (hp). c. e. If the fluid in the vessel has a vapor pressure of 20psi at the operating temperature, what is the maximum NPSHR allowed for the pump to prevent cavitation (psi)?

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Chapter7: Forced Convection Inside Tubes And Ducts
Section: Chapter Questions
Problem 7.33P
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A liquid (SG = 0.8 and μ = 5 CP = 0.00336 lbm/ft s) from a solvent recovery plant is being pumped
from a vessel into a reactor. The flow rate to the rector is 100 GPM (0.2228 ft³/s,) and the line,
schedule 40-carbon steel (a = 0.0018 in). The pressure in the vessel is 15 psig and the reactor is
pressurized to 65 psig. The flow into the reactor is 25 ft below the level in the vessel as shown in
the drawing. The centrifugal pump is located 5 ft below the level in the vessel.
The piping consists of the following:
Suction line
10 ft of 2.5"
Pipe
Gate valves
90 degree elbows
Check valves
2" sch 40 pipe
2.5" Sch 40 pipe
Gate valve
Check Valve
90° elbows
2
2
1
ID = 2.067"
ID=2.47"
K = 8 ft
K= 100 fr
K = 30 ff
Discharge line
325 ft of 2"
2
5
none
Acs=0.0233 ft²
Acs = 0.0332 ft²
a. Determine the velocity in the 2.5" and 2" lines (ft /s).
b. Determine the losses due to friction in both the suction and discharge lines (ft lbi/lbm).
c. Estimate the amount of total dynamic head required of the pump (ft lbi/lbm)
d.
If the pump is 80% efficient, determine the work required by the pump (hp).
e.
If the fluid in the vessel has a vapor pressure of 20psi at the operating temperature,
what is the maximum NPSHR allowed for the pump to prevent cavitation (psi)?
Transcribed Image Text:A liquid (SG = 0.8 and μ = 5 CP = 0.00336 lbm/ft s) from a solvent recovery plant is being pumped from a vessel into a reactor. The flow rate to the rector is 100 GPM (0.2228 ft³/s,) and the line, schedule 40-carbon steel (a = 0.0018 in). The pressure in the vessel is 15 psig and the reactor is pressurized to 65 psig. The flow into the reactor is 25 ft below the level in the vessel as shown in the drawing. The centrifugal pump is located 5 ft below the level in the vessel. The piping consists of the following: Suction line 10 ft of 2.5" Pipe Gate valves 90 degree elbows Check valves 2" sch 40 pipe 2.5" Sch 40 pipe Gate valve Check Valve 90° elbows 2 2 1 ID = 2.067" ID=2.47" K = 8 ft K= 100 fr K = 30 ff Discharge line 325 ft of 2" 2 5 none Acs=0.0233 ft² Acs = 0.0332 ft² a. Determine the velocity in the 2.5" and 2" lines (ft /s). b. Determine the losses due to friction in both the suction and discharge lines (ft lbi/lbm). c. Estimate the amount of total dynamic head required of the pump (ft lbi/lbm) d. If the pump is 80% efficient, determine the work required by the pump (hp). e. If the fluid in the vessel has a vapor pressure of 20psi at the operating temperature, what is the maximum NPSHR allowed for the pump to prevent cavitation (psi)?
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