a) Ln(-e i) = 1 – i

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A: Note : ejx = cos(x) + j sin(x) We will use this below :

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A: Given : (d) ∫02πdθa+bcos2θ2 where a, b > 0. To Find: Integral by Cauchy residue.

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A: consider complex numbers z1 and z2 as z1=r1cosθ1+isinθ1⇒z1=r1 , argz1=θ1z2=r2cosθ2+isinθ2⇒z2=r2 ,…

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A: The solution is:

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Q: 1 dx (9x² – 25)3

A: Please see the explanation below

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A: The given complex numbers are 1.   (1+i)2 2 .    12-32i6

Q: 17. COS Z

A: Solution