A long natural slope of cohesion-less soil is inclined at 12° to the horizontal. What will be the factor of safety of the slope if $ = 30°?
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![A long natural slope of
cohesion-less soil is
inclined at 12° to the horizontal. What will be
the factor of safety of the slope if $ = 30°?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feebeee85-6c8f-4cf7-8f48-99239da9f51e%2F0fb4254d-5bff-45c5-87df-bdf37a446e8c%2Fqy69k3_processed.jpeg&w=3840&q=75)
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- What is the greatest slope angle (B) of a slope formed by a cohesionless (C=0) sand? Assume the friction angle of the sand, o'= 28° O a. 280 Ob 350 OC. This sand cannot form a slope Od. Information is insufficient to determineA granular soil has Yeat = 18 kN/m³ and o' = 32°. An infinite slope is required to be made from %3D this material. If seepage occurs parallel to the surface of the slope and factor of safety of 1.5 is needed against slope failure then the value of safe angle of slope is degree.A cut slope is to be made in a clayey soil to permit construction of a new highway as shown below. A slope stability analysis is to be performed along the potential shear surface shown in the figure. The soils are silty clays with c' = 18 kPa, phi’ = 20degree. If the shear stress at point A is 60 kPa, compute the factor of safety against sliding at A. e ritag Existing ground surface Proposed - ground surface y=187 kN/m 49 m Y= 192 kNim² Proposed highway 15.2 m Potential shear surface levo ad o bas inns
- Describe why does slopesslopes in cohesionless soils may exist or be made atinclinations steeper than the soil’s angle of repose.Explain about the Noncircular slippage plane for slope stability analysis, Janbu method.In the given 15.0 meter slab and inclined 10°with the horizontal, the ends are resting on inclines of 30° incline at B and 20° at A, a semi-trailer truck is to pass through it with the wheel loads as shown. How Far (x, meters) shall be the front wheels located before motion impends, the angle of friction is 15° for all areas of contact. Neglect the weight of the slab 15.00 m 40 KN 32 KN 16 KN 24KN 3.6 m 4.0 m 1.2m 20° 30° 10°
- Stability of the following slope by a geotechnical engineer is being studied. The potential slip plane is shown. '= 30o for the ground and the cohesion is zero. The shear strength at point A is determined by the groundwater level. Determine when you are at the B and C levels. Dry and saturated unit volume of the ground their weights are respectively 18 and 19 kN / m3.1. The Maine DOT is constructing a section of the E-W highway along a 25 ft. high natural rock embankment. The slope of the rock face is 1.5H:1V. The DOT has requested a preliminary investigation of the factor of safety against slope instability. Rock cores gathered during the subsurface investigation indicate the predominant orientation of discontinuities varies between 9 and 19 deg. They are targeting a factor of safety of at least 1.5. Assuming a planar failure surface that extends through the toe and a friction angle of 25 degrees along the discontinuities: a. Plot the FS on the vertical axis for failure inclinations ranging between 9 and 19 degrees (horizontal axis). Is the required factor of safety satisfied? (Hint: create a spreadsheet and show one example calculation). H = 25 ft 1.5 Traffic Surcharge Pressure Failure surface Inclination, B Rock o'= 25 deg Y = 145 pcfA 35’ high slope has an angle of 18⁰ and is composed of saturated fine grained soils. The depth to bedrock below the toe of the slope is 17’. The soil has a unit weight of 119 PCF and an effective cohesion of 200 PSF. Determine the factor of safety using Taylor’s Chart.
- 4. A slope is 5 m high and has an angle of 45°. The soil parameters of the soil are: c'= 18 kN/m?, O'=15° and y = 17.1 kN/m³. Determine the factor of safety, Fs, using Michalowski's (2002) kinematic approach for c'-o' soils.Why does slope stabilty of the soil is dangerous in building construction?Calculate the factor of safety in terms of slope stability using the Cousin's Chart method of the soil, the information of which is given below
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