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A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest from a point 2 inches below the equilibrium position. Find the equation of motion. (Use g = 32 ft/s for the acceleration due to gravity.) x(t) = os 4V 6r ft

A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest from a point 2 inches below the equilibrium position. Find the equation of motion. (Use g = 32 ft/s for the acceleration due to gravity.) x(t) = os 4V 6r ft

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 18EQ
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A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest from a point 2 inches below the equilibrium position. Find the equation of motion. (Use g = 32 ft/s for the acceleration due to gravity.) x(t) = - cos 4V6r x ft COS
Transcribed Image Text:A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest from a point 2 inches below the equilibrium position. Find the equation of motion. (Use g = 32 ft/s for the acceleration due to gravity.) x(t) = - cos 4V6r x ft COS
A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest from a point 2 inches below the equilibrium position. Find the equation of motion. (Use g = 32 ft/s for the acceleration due to gravity.) x(t) = 2 cos 4V 6 t x ft
Transcribed Image Text:A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest from a point 2 inches below the equilibrium position. Find the equation of motion. (Use g = 32 ft/s for the acceleration due to gravity.) x(t) = 2 cos 4V 6 t x ft
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