A message signal m(t) (amplitude Am = 20 V, bandwidth BW=1 kHz) is input to FM Modulator 1 (ka generate gFMI(t). This signal is input to FM modulator 2 (kp = 2000n, carrier frequency fa %3D 500n, carrier frequency fel 30 kHz, output amplitude 8 V) to |3D = 2 MHz, output amplitude = 16 V). (Note: all modulators assume their input signals are baseband signals). a) b) c) Find BWFM1 (the bandwidth of gFM(t)) in Hz. Find BWFM2 (the bandwidth of gFM2(t)) in Hz. Find the power of gFM2(t). Find the range of instantaneous frequency of gFM1(t). Find the range of instantaneous frequency of gFM2(t). If we change Am, what value of Am will result in BWFM = 114 kHz? FM Modulator 1 k 500t fa-30 kHz Output Amp-8V FM Modulator 2 m(t) A-20 V BW=7kHz grun() ko = 2000r fa-2 MHz Output Amp-16 V 2.
A message signal m(t) (amplitude Am = 20 V, bandwidth BW=1 kHz) is input to FM Modulator 1 (ka generate gFMI(t). This signal is input to FM modulator 2 (kp = 2000n, carrier frequency fa %3D 500n, carrier frequency fel 30 kHz, output amplitude 8 V) to |3D = 2 MHz, output amplitude = 16 V). (Note: all modulators assume their input signals are baseband signals). a) b) c) Find BWFM1 (the bandwidth of gFM(t)) in Hz. Find BWFM2 (the bandwidth of gFM2(t)) in Hz. Find the power of gFM2(t). Find the range of instantaneous frequency of gFM1(t). Find the range of instantaneous frequency of gFM2(t). If we change Am, what value of Am will result in BWFM = 114 kHz? FM Modulator 1 k 500t fa-30 kHz Output Amp-8V FM Modulator 2 m(t) A-20 V BW=7kHz grun() ko = 2000r fa-2 MHz Output Amp-16 V 2.
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KVL and KCL
KVL stands for Kirchhoff voltage law. KVL states that the total voltage drops around the loop in any closed electric circuit is equal to the sum of total voltage drop in the same closed loop.
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Transcribed Image Text:A message signal m(t) (amplitude Am = 20 V, bandwidth BW =7 kHz) is input to FM
Modulator 1 (ka = 500, carrier frequency fel
generate gFMI(t). This signal is input to FM modulator 2 (ka = 2000n, carier frequency
fer
%3D
30 kHz, output amplitude = 8 V) to
!!
2 MHz, output amplitude = 16 V). (Note: all modulators assume their input signals
are baseband signals).
a)
b)
c)
d)
e)
%3D
Find BWFMI (the bandwidth of gFM(t)) in Hz.
Find BWFM2 (the bandwidth of gFM2(t)) in Hz.
Find the power of gFM2(t).
Find the range of instantaneous frequency of gFM(t).
Find the range of instantaneous frequency of gFM2(t).
If we change Am. what value of Am will result in BWEM = 114 kHz?
FM Modulator 1
FM Modulator 2
m(t)
A 20 V
BW 7kHz
= 500T
fr=30 kHz
Output Amp-8 V
kn = 2000r
fa-2 MHz
Output Amp 16 V
2.
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