A model rocket is launched with an initial velocity of 230 ft/s. The height, h, in feet, of the rocket t seconds after the launch is given byh = −16t2 + 230t.How many seconds after launch will the rocket be 770 ft above the ground? Round to the nearest hundredth of a second.s (smaller value)s (larger value)

Question
Asked Nov 24, 2019
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A model rocket is launched with an initial velocity of 230 ft/s. The height, h, in feet, of the rocket t seconds after the launch is given by

h = −16t2 + 230t.

How many seconds after launch will the rocket be 770 ft above the ground? Round to the nearest hundredth of a second.

s (smaller value)
s (larger value)
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Expert Answer

Step 1

A model rocket is launched with an initial velocity of 230 ft/s

and height, h, in feet, of the rocket t seconds after the launch is given by

h=-162230
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h=-162230

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Step 2

Time in seconds when the rocket be 770 ft above the ground is

770 16 230t
16t2-230t770 = .....(1)
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770 16 230t 16t2-230t770 = .....(1)

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Step 3

Using the quadrat...

-bb-4ac
if atbt+c 0 then t =-
2a
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-bb-4ac if atbt+c 0 then t =- 2a

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