Question

Asked Nov 24, 2019

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A model rocket is launched with an initial velocity of 230 ft/s. The height, *h*, in feet, of the rocket *t* seconds after the launch is given by

h = −16t^{2} + 230t.

How many seconds after launch will the rocket be 770 ft above the ground? Round to the nearest hundredth of a second.

s (smaller value) |

s (larger value) |

Step 1

A model rocket is launched with an initial velocity of 230 ft/s

and height, *h*, in feet, of the rocket *t* seconds after the launch is given by

Step 2

Time in seconds when the rocket be 770 ft above the ground is

Step 3

Using the quadrat...

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