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A multi-unit process first combusts propane and then removes water from the exhaust stream. The process is running at steady state. The company designing the process knows that they want to burn 60% of the propane (i.e. yield of CO; is only 60% of complete combustion of propane). The simple combustion reaction for propane is given below. Use the shortcut method to calculate the Degrees of Freedom around the Combustion Chamber.

A multi-unit process first combusts propane and then removes water from the exhaust stream. The process is running at steady state. The company designing the process knows that they want to burn 60% of the propane (i.e. yield of CO; is only 60% of complete combustion of propane). The simple combustion reaction for propane is given below. Use the shortcut method to calculate the Degrees of Freedom around the Combustion Chamber.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A multi-unit process first combusts propane and then removes water from the exhaust stream. The process is running at steady state. The company designing the process knows that they want to burn 60% of the propane (i.e. yield of CO, is only 60% of complete combustion of propane). The simple combustion reaction for propane is given below. Use the shortcut method to calculate the Degrees of Freedom around the Combustion Chamber. С3Н8 + 502 → 4H20 + 3CO2 Stream D Rate: D= ?? Composition: Du= 100% Stream A Rate: A = 0.4 mol/hour Composition: Охувеn: A-22.8% Nitrogen: Ay= 76.4 % Water:Aw=0.8% Stream E Rate: E- ??mol/s Composition: Охудen: F,- Nitrogen: Ey- Water: Ew- 2% Propane: Ep= co,: E- Combustion Condenser Chamber Stream C Stream B Rate: C- Rate: 8 = 0.01 mol/hour Composition: Propane: Bp= 100% Composition: Oxygen: Co= Nitrogen: Cy- Water: Cw- Propane: C,= co:C-
Transcribed Image Text:A multi-unit process first combusts propane and then removes water from the exhaust stream. The process is running at steady state. The company designing the process knows that they want to burn 60% of the propane (i.e. yield of CO, is only 60% of complete combustion of propane). The simple combustion reaction for propane is given below. Use the shortcut method to calculate the Degrees of Freedom around the Combustion Chamber. С3Н8 + 502 → 4H20 + 3CO2 Stream D Rate: D= ?? Composition: Du= 100% Stream A Rate: A = 0.4 mol/hour Composition: Охувеn: A-22.8% Nitrogen: Ay= 76.4 % Water:Aw=0.8% Stream E Rate: E- ??mol/s Composition: Охудen: F,- Nitrogen: Ey- Water: Ew- 2% Propane: Ep= co,: E- Combustion Condenser Chamber Stream C Stream B Rate: C- Rate: 8 = 0.01 mol/hour Composition: Propane: Bp= 100% Composition: Oxygen: Co= Nitrogen: Cy- Water: Cw- Propane: C,= co:C-
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