i need the answer quickly A parallel plate capacitor goes through 3 steps shown in+Q,-Q, +Q:-Q: +Q,-Q,Step 1Step 2Step 3step 1 all part do onlyStep 1:The gap between the two plates Is illed with a dlelectric slab of a dlelectric constant of 6.3. Theseparation between the two plates d= 0.054 mm. The area of each plate Is A = 0.037 m2. When thecapacitor Is fully charged, the amount of charge on each plate Is Q1 = 9.70 nCnc.inc = 10-9c.Part A - Step 1: what iš the capacitance C1?Part B - Step 1: Find the potential difference between the two plates Av1.Part C- Step 1: What is the magnitude of the electric field Eg in the gap of the capacitor?Part D - Step 1: What is the energy stored in the capacitor?Step 2:The charged capacitor In Step 1 remalns connected to the same charglng battery. The dielectric slabIs removed so that the gap between the two plates Is a vacuum. The separation between the twoplates Is unchanged d= 0.054 mm. The area of each plate Is unchanged A = 0.037 m2Part E- Step 2: calculate the magnitude of the electric field in the gap, E2Part F - Step 2: what is the capacitance C2?Part G - Step 2: what is the amount of charge Q2 on each plate?Step 3 The charged capacitor In step 2 Is DISCONNECTED from the charglng battery. The plate areaIs unchanged at the original value o.037 m2. The gap separatlon Is changed to 3/4 of the orlginald, d3 = 0.0405 m.Part H - Step 3: What is the capacitance C3?Part I- Step 3: What is the potential difference between the two platesAV3.?area

Answered: Image /qna-images/answer/1a731a56-a97b-4941-8c6d-a51a601fd840.jpg

Step 1: The gap between the two plates Is filled with a dlelectric slab of a dlelectric constant of 6.3. The separation between the two plates d = 0.054 mm. The area of each plate Is A = 0.037 m2. When the capacitor Is fully charged, the amount of charge on each plate Is Q1 = 9.70 nCnC. 1nc = 10-9 c. Part A - Step 1: what is the capacitance C1? Part B - Step 1: Find the potential difference between the two plates AV1. Part C- Step 1: What is the magnitude of the electric field Ej in the gap of the capacitor? Part D - Step 1: What is the energy stored in the capacitor?

Step 1: The gap between the two plates Is filled with a dlelectric slab of a dlelectric constant of 6.3. The separation between the two plates d = 0.054 mm. The area of each plate Is A = 0.037 m2. When the capacitor Is fully charged, the amount of charge on each plate Is Q1 = 9.70 nCnC. 1nc = 10-9 c. Part A - Step 1: what is the capacitance C1? Part B - Step 1: Find the potential difference between the two plates AV1. Part C- Step 1: What is the magnitude of the electric field Ej in the gap of the capacitor? Part D - Step 1: What is the energy stored in the capacitor?