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CalculusQ&A LibraryA particle moves along a straight line and its position at time t is given by s(t)=2t^3−24t^2+72t where s is measured in feet and t in seconds. Find the velocity (in ft/sec) of the particle at the time when the acceleration is 0? The particle changes direction twice from positive to negative at time? and from negative to positive at time?Start your trial now! First week only $4.99!*arrow_forward*

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A particle moves along a straight line and its position at time t is given by s(t)=2t^3−24t^2+72t where s is measured in feet and t in seconds.

Find the velocity (in ft/sec) of the particle at the time when the acceleration is 0?

The particle changes direction twice from positive to negative at time?

and from negative to positive at time?

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